Josh "Ooson" Post

https://www.smore.com/h71kx-making-sense-of-math

                                                             



Hi. Welcome to my scribe post about 2 step Algebra. In our previous math class Mr. Harbeck taught us how to solve 2 step problems.

The two problems I will be solving are:
3x-7+2x=9
-n+5+21n=0

Here is how you solve it:

                                                                    
         3x-7+2x=9                                      
        5x-7+7=9+7                                                        
             5x=16
              5     5
              x=3.2

First Step: Do Combining Like Terms by adding 3x and 2x to make it into 5x
Second Step: Re-write the problem so that the coefficient, variable, and constant goes first and the answer is last. Make sure to take away the -7 out by adding +7 which will give you 9+7=16
Third Step: After that you get 5x=16. To isolate the variable, you will need to divide 5x and 16 by 7
x=3.2


Here is how you solve the second question:


                     -n+5+21n=0
                        20n+5=0
                     20n+5-5+0-5
                         20n=-5 ÷ 5
                         20   20 ÷ 5
                             x=-¼

First Step: Combining Like Terms. Add -n (-1n) and 21n
Second Step: Re-write the question,make sure to take away the +5 by adding -5 to it.
Third Step: When you get 20n=-5, you divide that by 5/5. 
x=-¼



               


       












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4 comments:

  1. sorry,my brain is still a pebble. i cant verify when multiplying fractions.

    ReplyDelete
  2. Ask Questions in class! We can help there

    ReplyDelete
  3. Like Harbeck said, just ask in class and we'll help you figure it out.

    ReplyDelete